For a school field trip the students had two options for lunch, a turkey or egg salad sandwich, so it is impossible for a student have both lunches. if the probability that a student chooses a turkey sandwich is 0.10, and the probability that a student chooses an egg salad sandwich is 0.67, what is the probability that a student chooses a turkey or egg salad sanwich?

0.77

Step-by-step explanation:

Given :  Probability that a student chooses a turkey sandwich is

P(Turkey )= 0.10

Probability that a student chooses an egg salad sandwich is

P(egg salad)=0.67

Also, it is impossible for a student have both lunches.

∴ P(Turkey and egg salad) =0

Now , the probability that a student chooses a turkey or egg salad sandwich will be

P(Turkey or egg salad) =  P(Turkey )+ P(egg salad)- P(Turkey and egg salad)

=  0.10+ 0.67-0 = 0.77

Hence, the probability that a student chooses a turkey or egg salad sandwich= 0.77

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

answer:

sometimes

*i think