The perimeter of a rectangle is 40 inches the width is 8 inches shorter than the length find the dimensions of the rectangle

Main equation:

2L + 2w = 40

We know that

w = L - 8

Substitute in known value

2L + 2(L - 8) = 40

Solve

2L + 2L - 16 = 40

4L = 24

L = 6

Length = 6 inches

Width =  14 inches

Hope this helps :)

there is no question content here, but you for the free points! : d

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)