In many population growth problems, there is an upper limit beyond which the population cannot grow. many scientists agree that the earth will not support a population of more than 16 billion. there were 2 billion people on earth in 1925 and 4 billion in 1975. if is the population years after 1925, an appropriate model is the differential equation
dy/dt=ky(16-y)

note that the growth rate approaches zero as the population approaches its maximum size. when the population is zero then we have the ordinary exponential growth described by y'=16ky. as the population grows it transits from exponential growth to stability.

(a) solve this differential equation.
(b) the population in 2015 will be
(c) the population will be 9 billion some time in the year

i want to die

what the hell man, i just want the points lol

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.