The number of rescue calls received by a rescue squad in a city follows a poisson distribution with an average of 2.83 rescues every eight hours. what is the probability that the squad will have at most 2 calls in an hour? round answer to 4 decimal places.

There is a 99.44% probability that the squad will have at most 2 calls in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which

x is the number of sucesses

e = 2.71828 is the Euler number

is the mean in the given time interval.

In this problem, we have that:

2.83 rescues every eight hours.

What is the probability that the squad will have at most 2 calls in an hour?

This is

We have 2.83 rescues every 8 hours. So for an hour, we have

So

So

There is a 99.44% probability that the squad will have at most 2 calls in an hour.

sorry i need the points

step-by-step explanation:

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