In triangle abc, bc=4cm, ad=3cm. the triangle abc moves upward at the speed of 4cm per seconds. what is the area swept by the triangle in three seconds?

Step-by-step explanation:

Area Of Triangle And Rectangle

Given a triangle of base b and height h (perpendicular to b), the area can be computed by

A rectangle of the same dimensions has an area of

We have a triangle of base 3 cm and a height of 4 cm. Its area is

That triangle moves upward at 4 cm per second for 3 seconds. It means that the triangle 'sweeps' upwards three times its height forming a rectangle of base 3 cm and height 12 cm. The area of the swept area is

The triangle stays in the top of this rectangle, so its area is part of the total swept area:

Total swept area = 6 + 36 =

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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step-by-step explanation: