The length of a rectangle is twice the width of the rectangle the length of a diagonal of the rectangle is 25cm work out the ares of the rectangle give your answer as an integer

Area is 50 cm^2

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The formula for determining the area of a rectangle is expressed as

Area = LW

The length of a rectangle Is twice the width of the rectangle. This means that

L = 2W

The length of a diagonal of the rectangle is 25cm. This is the hypotenuse of the right angle triangle that is formed. Applying Pythagoras theorem,

25^2 = L^2 + W^2 - - - - - - - 1

Substituting L = 2W into equation 1, it becomes

25^2 = (2W)^2 + W^2

25^2 = 4W^2 + W^2 = 5W^2

Taking square of both sides,

W = √25 = 5

L = 2W = 3×5 = 10

Area = LW = 10×5 = 50 cm^2

cant open file sorry!

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk