Nola hiked down a trail at a steady rate for 10 minutes. her change in elevation was -200 feet. then she continued to hike down another 20 minutes at a different rate. her change in elevation for this part of the hike was -300 feet. during which portion of the hike did she walk down at a faster rate? explain your reasoning.

The correct answer is:

The faster rate is when she hiked down 200 feet in 10 minutes.

Explanation:

The rate of change is given by the change in y over the change in x; in this case, the change in elevation over the change in time.

For the first part of the hike, the change in elevation was -200 and the change in time was 10; this gives us a rate of change of -200/10 = -20.

For the second part of the hike, the change in elevation was -300 and the change in time was 20; this gives us a rate of change of -300/20 = -15.

She hiked downhill faster during the first part of the hike, at 20 feet per minute.

c-4 is the final answer! : )

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

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}

step-by-step explanation: