When x=3, y=16 and when x=6, y=8. which inverse variation equation can be used to model this function

Inverse variation equations take the following form:

y = a/x, where a is some constant

We know x=3, y=16 and x=6, y=8 satisfy the equation.

Let's find the value of a.

16=a/3

Multiply both sides by 3

16*3 = a

48 = a

Thus, the equation is:

y = 48/x

You can use the other values of x and y to test, but I'm sure this is the correct equation. :)

(This answer was sent on mobile, so please pardon any spelling errors I may have)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

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