Find the ph of a 0.135m aqueous solution of periodic acid(hio4) for which ka= 2.3 x 10^-2

a. 1.17
b. 3.28
c. 1.34
d. 1.23
e. 1.84

The answer is C. pH= 1.34

Step-by-step explanation:

Periodic acid dissociates in water as:

HIO4 ⇒ H⁺ +  IO₄⁻

The formula for Ka is:

where:

[H⁺] = concentration of H+ ions

[B-] = concentration of conjugate base ions

[HB] = concentration of undissociated acid molecules

for a reaction HB ⇒  H⁺ + B⁻

Periodic acid dissociates one H⁺ ion for every  IO₄⁻ ion, so [H⁺] = [  IO₄⁻].

Let x represent the concentration of H⁺ that dissociates from HB, then [HB] = C - x where C is the initial concentration.

Then, by using the Kₐ formula:

x² + Kₐx - CKₐ = 0

So the dissociated concentration is:

x= 0.0454

The pH of the solution is:

pH= - log[0.0454]= 1.34

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363