Box contains the following numbered tickets: 1,1,5,9,9 a) if i draw two tickets with replacement, what is the chance that the sum of the two tickets is greater than or equal to 10?

17/25

Step-by-step explanation:

The probability of drawing 1 = 2/5

The probability of drawing 5 = 1/5

The probability of drawing 9 = 2/5

Since the sum of the two ticket is greater than or equal to 10,

If I draw 1 first, I can only only select 9 also= 2/5* 2/5

= 4/25

If I draw 5, I can draw another 5 or 9 later = 1/5 * (1/5+2/5)

= 1/5 * 3/5

= 3/25

If I draw 9 then I can draw anything

2/5 * 5/5

= 10/25

The sum of all the products = 4/25 + 3/25 + 10/25

= 17/25

i think the correct option is the second option.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497