At local ice cream store, you can purchase one, two, or three scoops of ice cream. you also have a choice of either a sugar cone or a waffle cone. based on the average daily sales from the past week, 60% of the customers purchase a waffle cone, 40% of the customers purchased two scoops of ice cream, and 20% purchased both. based on the average daily sales from last week, what is the probability a randomly selected customer purchases two scoops of ice cream if we know the customer purchased a waffle cone?

33.3% probability a randomly selected customer purchases two scoops of ice cream if we know the customer purchased a waffle cone.

Step-by-step explanation:

In this problem, we have these following probabilities:

A 60% probability that a customer purchases a waffle cone.

A 20% probability a person person purchases both a waffle cone and two scoops of ice cream.

Based on the average daily sales from last week, what is the probability a randomly selected customer purchases two scoops of ice cream if we know the customer purchased a waffle cone?

This is 0.2/0.6 = 0.333 = 33.3% probability a randomly selected customer purchases two scoops of ice cream if we know the customer purchased a waffle cone.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!