Alottery game requires that you pick 66 different numbers from 1 to 7575. if you pick all 66 winning numbers, you win the jackpot. if you pick 55 of the 66 numbers correctly, you win $250 comma 000250,000. in how many ways can you pick exactly 55 of the 66 winning numbers without regard to order?

1.074×10^12 ways

Step-by-step explanation:

Number of ways is given by n combination r

n combination r = n!/(n-r)!r!

n = 66, r = 55

66 combination 55 = 66!/(66-55)!55! = 66!/11!55! = (66×65×64×63×62×61×60×59×58×57×56×55!)/(11×10×9×8×7×6×5×4×3×2×1×55!) = (66×65×64×63×62×61×60×59×58×57×56)/(11×10×9×8×7×6×5×4×3×2×1) = 1.074×10^12

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4