Four students have a plan for a movie night where they have three options, movie a, movie b, movie c. they decide that they would not let any individual go for the movie along , what’s the number of all possible plans ?

Total number of possible plans = 9

Step-by-step explanation:

Four students have a plan for a movie night where they have three options, movie A, movie B, movie C. They decide that they would not let any individual go for the movie alone.

So they can go in two groups of 2 or in a group of 4.

If they go in two groups of 2 ,the possible cases are selecting any 2 movies out of the 3 and also selecting which group sees which movie.

So total cases = 3 2 = 6

If they all go as a group there are only 3 cases as they can go for any of the movie.

So the total number of cases = 6 + 3 = 9

i would go with the first one

step-by-step explanation:

hope this

the two may have that, even a breakdown is probably offered