For each of the following relations r on the set x decide whether r is reflexive, symmetric, (weakly) antisymmetric or transitive: (a) x = z, arb if and only if a ≤ b + 1; (b) x = z, arb if and only if a + b is even; (c) x = p, arb if and only if a and b are coprime: (d) x = z, arb if and only if a + b is divisible by 3; (e) x = r, arb if and only if a2 ≤ b2; (f ) x = r × r, (a, b)r(c, d) if and only if a = c; (g) x = n × n, (a, b)r(c, d) if and only if either a < c or(a = c and b ≤ d).

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

umumumumum

im not sure

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204