me i dont understand this one!
(05.01 mc)

in δabc shown below, segment de is parallel to segment ac :

triangles abc and dbe where de is parallel to ac

the following two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally:

statement reason

1. line segment de is parallel to line segment ac 1. given

2. line segment ab is a transversal that intersects two parallel lines. 2. conclusion from statement 1.

3. 3.

4. 4.

5. δabc ∼ δdbe 5. angle-angle (aa) similarity postulate

6. bd over ba equals be over bc 6. converse of the side-side-side similarity theorem

which statement and reason accurately completes the proof? (5 points)

3. ∠bde ≅ ∠bac; corresponding angles postulate

4. ∠a ≅ ∠c; isosceles triangle theorem

3. ∠bde ≅ ∠bac; alternate interior angles theorem

4. ∠a ≅ ∠c; isosceles triangle theorem

3. ∠bde ≅ ∠bac; corresponding angles postulate

4. ∠b ≅ ∠b; reflexive property of equality

3. ∠bde ≅ ∠bac; alternate interior angles theorem

4. ∠b ≅ ∠b; reflexive property of equality