The children between ages of 2 and 5 watch an average of 25 hours of tv per week. assume that standard deviation is 3 hours of tv per week, if a sample 20 children between ages of 2-5 are randomly selected with the mean sample of 26.3. find the probability that the mean number of hours they watch tv is greater than 2.6 hours.

the probability that the mean number of hours they watch TV is greater than 26.3 hours is 0.034

Step-by-step explanation:

Last part of the question is wrong. It should be:

Find the probability that the mean number of hours they watch TV is greater than 26.3 hours.

P('the mean number of hours the children between ages of 2 and 5 watch TV' >26.3 hours) = P(t>t*) where

t* is the t-score of 26.3 hours. It can be found using the equation:

where

: ≈1.938

Corresponding p-value with 19 degrees of freedom: P(t>1.938)  is  ≈ 0.034

step-by-step explanation:

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