Using the standard normal distribution, find the two z-scores that that form the middle shaded region. the shaded region is symmetric about z = 0 . round your z-scores to two decimal places.

Between (-0.675, 0.675)

Step-by-step explanation:

We know that a standard normal distribution curve is bell shaped unimodal , symmetrical about mean.

for thsi standard normal variate with notation z, we get mean =0 and std deviation = 1

For the middle shaded region, we find z such that the area between -z and z is 0.50 exactly half.

From standard normal distribution table, we get that z= ±0.675

Hence between z=-0.675 and z = 0.675 we get the middle region with area equal to exactly 1/2.

Between (-0.675, 0.675)

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

c

-by-step explanation:

it would be c