(asap)

what is the equation of a line with a slope of -2(m= -2) that passes through the point (0,5)?

slope:

equation of a line:

Step-by-step explanation:

The given point is the y-intercept of the line, so the slope-intercept form of the equation of a line can be used:

  y = mx + b . . . . for slope m and y-intercept b

Here, you have the slope given as ...

  m = -2

  y-intercept = 5

so the equation of the line is ...

  y = -2x +5

The y-intercept is the value of y when x=0. The point (x, y) = (0, 5) tells you the y-intercept is 5.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: