Agarden in the shape of a right triangle has sides measuring 60, 80 and 100 ft. the owner of the garden adds a new section of fence that runs from the right angle to the hypoteneuse and separates the garden into two parts of equal perimeter. find the length of the new section of the fence. problem is not out of a textbook, rather on a worksheet.

The answer is 48 ft

Step-by-step explanation:

Step 1:

The garden before the fence is: (refer to graphical representation in attached file)

o = side

b = base

h= hypotenuse  

Use Sin (t) formula;

Sin (t) = o/h

Sin (t) = 80/100

Sin (t) = 0.8

Step 2:

The garden was divided in 2 parts and a is the missing length which needed to be found (refer to graphical representation in attached file)

For Small triangle (refer to graphical representation in attached file);

a = side

c = base

b= hypotenuse  

Use Sin (t) formula;

Sin (t) = a/b

0.8 = a/60

A = 0.8x60

A = 48 ft

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

hope this !

~just a girl in love with shawn mendes