The hour hand of a clock is 6 inches long and the minute hand is 8 inches long. what is the ratio of the distance in inches traveled by the tip of the hour hand to the distance in inches traveled by the tip of the minute hand from noon to 3 p. m. ?

the ratio of the distance in inches travelled by the tip of the hour hand to the distance in inches travelled by the tip of the minute hand is 0.125.

Step-by-step explanation:

The given information is:

Therefore, since the tip of the minute moves from 12 to 3, it moved a distance of:

s₁ = r θ

s₁ = (8)(π/2)

s₁ = 4π inches                                                                      

The hour hand moves 30 degrees / 60 = 1/2 degree in a minute.

Therefore, in 30 minutes the hour hand moves a distance of:

s₂ = r θ

s₂ = 6(30×1/2×π/180)

s₂ = π/2 inches                                                                              

Therefore, the ratio of the distance in inches travelled by the tip of the hour hand to the distance in inches travelled by the tip of the minute hand is:

s₂ / s₁ = (π/2) / 4π

s₂ / s₁ = 0.125

30 feet

step-by-step explanation:

that would be 2 1/2 * 12

= 24 + 6

= 30 feet   (answer)

the correct answer would be d because the slope is -2/2=1 and the y intercept is at 2 so that is the correction equation