Mathematics, 23.12.2019 23:31 HeartfeltDream12

Obtain or compute the following quantities.

(a) f0.05, 4, 7 (round your answer to two decimal places.)
(b) f0.05, 7, 4 (round your answer to two decimal places.)
(c) f0.95, 4, 7 (round your answer to three decimal places.)
(d) f0.95, 7, 4 (round your answer to three decimal places.)
(e) the 99th percentile of the f distribution with v1 = 8, v2 = 12 (round your answer to two decimal places.)
(f) the 1st percentile of the f distribution with v1 = 8, v2 = 12 (round your answer to three decimal places.)
(g) p(f ≤ 6.26) for v1 = 5, v2 = 4 (round your answer to two decimal places.)
(h) p(0.177 ≤ f ≤ 4.74) for v1 = 10, v2 = 5 (round your answer to two decimal places.)

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Answer from: isudgyia

a) $F_{0.05,4,7}=0.16$

b) $F_{0.05,7,4}=0.24$

c) $F_{0.95,4,7}=4.12$

d) $F_{0.95,7,4}=6.09$

e) $F_{0.99,8,12}=4.50$

f) $F_{0.01,8,12}=0.18$

g) $P(F_{5,4} \leq 6.26)=0.95$

h) $P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

$F_{0.05,4,7}=0.16$

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

$F_{0.05,7,4}=0.24$

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

$F_{0.95,4,7}=4.12$

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

$F_{0.95,7,4}=6.09$

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

$F_{0.99,8,12}=4.50$

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

$F_{0.01,8,12}=0.18$

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

$P(F_{5,4} \leq 6.26)=0.95$

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

$P(0.177 \leq F_{10,5} \leq 4.74)=0.94$

Answer from: Quest

answer: jasmine will bake 4/3 or 1 1/3 cookies in an hour

step-by-step explanation:

if u add 1/3 every 15 minutes after an hour u will have 4/3 or 1 1/3

Answer from: Quest

Ifound this on google “that means that the graph of a function with direct variation has these features: it is a straight line: because the slope is the ratio y/x = k. it passes through the origin (0,0): because y = kx = k (0) = 0.” i hope this you for what your looking for

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Obtain or compute the following quantities.

(a) f0.05, 4, 7 (round your answer to two d...

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