Suppose $p,$ $q,$ and $r$ are points in the plane such that $pq=1.8,$ $pr=8.2,$ and $\angle pqr=90^\circ$. what is the perimeter of $\triangle pqr$?

Perimeter of triangle is 18.

Step-by-step explanation:

Given:

segment PQ = 1.8

segment PR = 8.2

∠PQR =90°

Since triangle is a right angle triangle with right angle at ∠Q.

Now by using Pythagoras theorem we get;

The square of one side is equal to sum  of the square of other two side.

Substituting the given value we get;

Now taking square root on both side we get;

Now we need to find the perimeter of the triangle.

Perimeter of triangle is sum of all three side.

Framing in equation form we get;

Perimeter of triangle = PQ + QR +PR = 1.8 + 8 + 8.2 = 18

Hence Perimeter of triangle is 18.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

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step-by-step explanation:

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