Asolid right circular cone of diameter 14cm and height 8cm is melted to form a hollow sphere. if the external diameter of the sphere is 10cm, find the internal diameter of the sphere

Step-by-step explanation:

Diameter of cone=14 cm

so, Radius of cone= 7cm

     Height of cone= 8cm

     ∴ Volume of cone= 1/3*pi*r^2*h

                                 =1/3*pi*49*8 cm^3

In Sphere, External Radius R=5cm

         Let, Internal Radius = r  

   Volume of Sphere = External Volume- Internal Volume

                                 = 4/3*pi*R^3-4/3*pi*r^3

                                 =4/3*pi[R^3-r^3]

                                 =4/3*pi[5^3-r^3]

But During Conversion Volume Remains Same

    So, Volume of Sphere=Volume of Cone

           4/3*pi[125-r^3]= 1/3*pi*49*8

           4[125-r^3]=49*8

             [125-r^3]=49*2

              r^3=125-98

              r^3=27

              so, r =3 cm

          Internal Radius= 3cm

   So, Internal Diameter=3*2= 6cm

PLS MARK BRAINLIEST

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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step-by-step explanation: