Find two consecutive integers such that twice the larger is the same as two less than three times the smaller.

Ans => 4, 5

Step-by-step explanation:

let the integers be x and y

if they are consecutive, that means the larger integer is one greater than the smaller

=> y = x+1

2 = 3x - 2y

3x - 2(x+1) = 2

3x - 2x - 2 = 2

x = 4

y = 4+1 = 5

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

i need points

step-by-step explanation:

sorry bubs