Abigail is raising money for a school trip by selling bags of chips and packs of cookies. the price of each bag of chips is $1.50 and the price of each pack of cookies is $1.25. yesterday abigail made $27 from selling a total of 20 bags of chips and packs of cookies. determine the number of bags of chips sold and the number of packs of cookies sold

The number of bags of chips sold is 8 and the number of packs of cookies sold is 12

Solution:

Let "a" be the number of bags of chips sold

Let "b" be the number of packs of cookies sold

Given that,

Cost of one bag of chips = $ 1.50

Cost of one pack of cookies = $ 1.25

Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies

So we can frame a equation as:

Number of bags of chips sold + number of packs of cookies sold = 20

a + b = 20 ---- eqn 1

Also given that Abigail made $27 from selling

number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27

1.5a + 1.25b = 27 ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "b"

From eqn 1,

a = 20 - b ---- eqn 3

Substitute eqn 3 in eqn 2

1.5(20 - b) + 1.25b = 27

30 - 1.5b + 1.25b = 27

-0.25b = -3

Therefore from eqn 3,

a = 20 - b = 20 - 12 = 8

Thus we have:

number of bags of chips sold = 8

number of packs of cookies sold = 12

11 feet 6 inches and 8 feet 6 inches

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )