When the air temperature is a constant 70f, an object cools from 170f to 140f in one half-hour. what is the temperature of this object after 1 hour? equation: t(t)=ts+(to-ts)e^(-kt)

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step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right