Give a button and a bookmark
to each student who visited the fair. the buttons came in
packages of 30. the bookmarks came in packages of 50.
the committee needed the same number of each left
over for another fair. the committee estimated that
400 students would visit the fair. how many
packages of buttons and packages of bookmarks
did they need?

15 packages of buttons

9 packages of bookmarks

Step-by-step explanation:

We need to find the least common multiple (LCM) of 30 and 50.

30 = 2×3×5

50 = 2×5²

LCM = 2×3×5²

LCM = 150

Now we need to find a multiple of LCM that is greater than 400.

3LCM = 450

The committee needs at least 450 of each, which means they need at least 15 packages of buttons and 9 packages of bookmarks.

i hope this is what you were looking for.

see attached graph

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: