Wyatt walks 3 miles each day for 6 days. aaliyah walks 4 1/2 miles each day for 6 days. how many more miles will aaliyah walk in 6 days than wyatt

It can be deduced that Aaliya walks 9 miles farther than Wyatt in 6 days.

Wyatt walks 3 miles each day for 6 days. The number of total miles will be:

= 6 × 3 = 18 miles

Aaliyah walks 4 1/2 miles each day for 6 days. The number of total miles will be:

= 4 1/2 × 6 = 27 miles.

Therefore, the difference will be:

= 27 miles - 18 miles = 9 miles.

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Aaliya walks 9 miles farther than Wyatt in 6 days.

Step-by-step explanation:

The distances walked are as follows:

Wyatt:  (3 mi/day)(6 days) = 18 mi

Aaliyah:  (4.5 mi/day)(6 days) = 27 miles

Aaliya walks 9 miles farther than Wyatt in 6 days.

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.