Arhombus has side lengths of 25. what could be the lengths of the diagonals?

25√2

For the opposite side, the hypotenuse, a rhombus is always divided by a angle bisector. Therefore you use the 45-45-90 theorem

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

id

step-by-step explanation:

idk

idk

i know the way

and

idk