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Mathematics
, 10.10.2019 16:00
ishmael9332
C:
what are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10
(−4, −2) and (2, 5)
(−2, −4) and (2, 5)
(−2, −4) and (5, 2)
no real solutions
Answers: 3
Show answers
Answers
Answer from:
hanjonez
2nd equation:
8 x-y=10 ⇒ y= 8 x-10
We will switch that in 1st equation:
8 x-10=x²+12 x+30, or:
x² + 4 x +40 = 0, a=1,B=4, c=40
Discriminant : D= b² - 4 ac= 16 - 160 = -144 and because it is negative there are no real solutions.
D)
Answer from:
Lesquirrel
Hello,
y=x²+12x+30
y=8x-10
==>x²+12x+30=8x-10
==>x²+4x+40=0
Δ=16-4*40<0 ==> no real solutions.
Answer from: Quest
256825) wjjikbhjkxk$: 882&
Answer from: Quest
the answer is 62
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C:
what are the solutions to the following system of equations?
y = x2 + 12x + 30
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