Steve thinks that he has a fair coin with equal probability of landing head or tails. he is ready to change his mind if in a long enough series of flips the coin will land on the same side. steve decided that "long enough" means the probability of a fair coin landing the same way is less than 1%. what is the shortest series that will allow steve to declare that the coin is not fair?

a. 7 flips

b. 8 flips

c. 99 flips

d. 101 flips

maybe c idk

A. 7 flips

Step-by-step explanation:

the shortest series that will allow Steve to declare that the coin is not fair = n

The probability of a coin tossed n times to land on the same side is given as;

Pn =1/2^n

For Pn < 1% = 0.01

1/2^n < 0.01

nLog(1/2) < Log (0.01)

n > Log(0.01)/Log(1/2)

n > 6.64

The shortest n = 7

Therefore, the shortest series that will allow Steve to declare that the coin is not fair

= 7 flips.

b

step-by-step explanation:

this answer is !