Mathematics, 19.12.2019 02:31 jose477

In a local university, 40% of the students live in dormitories. a random sample of n = 80 students is selected for a particular study.
(a) what is the sampling distribution of p? provide its general shape, its standard deviation, and its mean.
(b) what is the probability that the sample proportion (the proportion living in the dormitories) is between 0.30 and 0.50?

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Answer from: lizzyyyvv

a) p is normally distributed with mean P = 0.4 and standard deviation

δ = 0.05477

b) P( 0.3 < p < 0.5) = 0.9312

Step-by-step explanation:

a) What is the sampling distributión of P?

p(sample proportion) is normally distributed with mean P and standard

deviation δ = $\sqrt{\frac{P(1-P)}{n} }$

how P = 0.40 population proportion of the students live in dormitories,

then p is normally distributed with mean P = 0.4 and standard deviation

δ = $\sqrt{\frac{0.4(1-0.4}{80} }$

δ = 0.05477

b) P( 0.3 < p < 0.5)

Standardizing

z = (p - P)/δ

$z_{1} = \frac{0.3-0.4}{0.05477}$

= -1.82

$z_{2} = \frac{0.5-0.4}{0.05477}$

= 1.82

P(-1.82 < z < 1.82) = P(z < 1.82) - P(z<-1.82)

=0.9656 - 0.0344

P(-1.82 < z < 1.82) = 0.9312

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.

Answer from: Quest

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation:

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