How can the angle-angle similarity postulate be used to prove the two triangles below are similar? explain your answer using complete sentences, and provide evidence to support your claims.

Explanation with Proof is given below.

Step-by-step explanation:

Given:

In  Δ ABC,

m∠ A = 59°

m∠ B = 37°

In Δ A'B'C'

m∠ A' = 59°

m∠ C' = 84°

To Prove:

Δ ABC ~ Δ A'B'C'

Proof:

In  Δ ABC we have,

m∠ A + m∠ B + m∠ C = 180° {Angle Sum Property of Triangle}

Substituting the given values we get

Now,

In  Δ ABC and Δ  A'B'C'

∠ A ≅ ∠ A'     …………..{measure of each angle is 59°}

∠ C ≅ ∠ C'     ……….{measure of each angle is 84°}

Δ ABC ~ Δ A'B'C'  ….{ By Angle-Angle Similarity Postulate} Proved

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

hdjd

step-by-step explanation: