Mathematics, 19.12.2019 00:31 Trup1822
Atv station claims that 38% of the 6: 00 - 7: 00 pm viewing audience watches its evening news program. a consumer group believes this is too high and plans to perform a test at the 5% significance level. suppose a sample of 830 viewers from this time range contained 282 who regularly watch the tv station’s news program. carry out the test and compute the p-value.
Answers: 3
Mathematics, 21.06.2019 15:50
3-12. write each answer with a reasonable number of figures. find the absolute uncertainty and percent relative uncertainty for each answer. (a) [12.41 (±0.09) + 4.16 (±0.01)] x 7.068 2 (±0.000 4) =? (b) [3.26 (±0.10) x 8.47 (±0.05)] - 0.18 (±0.06) =? (c) 6.843 (±0.008) x 104 + [2.09 (±0.04)- 1.63 (±0.01)] =?
Answers: 1
Mathematics, 21.06.2019 21:30
Alcoa was $10.02 a share yesterday. today it is at $9.75 a share. if you own 50 shares, did ou have capital gain or loss ? how much of a gain or loss did you have ? express the capital gain/loss as a percent of the original price
Answers: 2
Mathematics, 22.06.2019 00:00
Heather is a cashier. she can ring up 1212 customers in 99 minutes. at this rate, how many minutes does it take her to ring up 44 customers?
Answers: 1
Atv station claims that 38% of the 6: 00 - 7: 00 pm viewing audience watches its evening news progra...
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