N2000, researchers investigated the effect of weed-killing herbicides on house pets. they examined 832 cats from homes where herbicides were used regularly, diagnosing malignant lymphoma in 420 of them. of the 145 cats from homes where no herbicides were used, only 17 were found to have lymphoma. find the standard error of the difference in the two proportions.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

1) Data given and notation  

represent the number of cats diagnosing malignant lymphoma from homes where herbicides were used regularly

represent the number of cats diagnosing malignant lymphoma from homes where NO herbicides were used regularly

sample 1 selected

sample 2  selected

represent the proportion of of cats diagnosing malignant lymphoma from homes where herbicides were used regularly

represent the proportion of cats diagnosing malignant lymphoma from homes where NO herbicides were used regularly

z would represent the statistic (variable of interest)  

represent the value for the test (variable of interest)  

parameter of interest

2) Solution to the problem

We are interested on the standard error for the difference of proportions and is given by this formula:

And if we replace the values given we got:

dude thats to long figure it

step-by-step explanation: