In a certain algebra 2 class of 30 students, 12 of them play basketball and 17 of them
play baseball. there are 5 students who play neither sport. what is the probability
that a student chosen randomly from the class plays both basketball and baseball?

The probability of students playing both basketball and baseball =

Step-by-step explanation:

Total strength of class = 30 students

Number of students who play basketball = 12

Number of students who play baseball = 17

Number of students who play neither sport = 5

Number of students that play either sport = = 25

Number of students who play both sports will be given as:

⇒ Number of students playing basketball + Number of students playing baseball - Number of students playing either

⇒

⇒

Thus probability of students playing both basketball and baseball is given as:

⇒

⇒

Dividing numerator and denominator by 2 to reduce to simplest fraction.

⇒

⇒ (Answer)

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i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.