The third term in a geometric sequence is -81. the common ratio is 1/3

what is the second term of the sequence?

if you answer, can you explain it?

Step-by-step explanation:

The formula for the nth term of a geometric sequence is expressed as follows

Tn = ar^(n - 1)

Where

Tn represents the value of the nth term of the sequence

a represents the first term of the sequence.

n represents the number of terms.

From the information given,

r = 1/3

T3 = - 81

n = 3

Therefore,

- 81 = a× 1/3^(3 - 1)

-81 = a × (1/3)^2

-81 = a/9

a = -81 × 9 = - 729

The exponential equation for this sequence is written as

Tn = - 729 * (1/3)^(n-1)

Therefore, to find the second term,T2, n = 2. It becomes

T2 = - 729 * (1/3)^(2-1)

T2 = - 729 * (1/3)^1

T2 = - 729 * (1/3)

T2 = - 243

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

is only a line? i think so