What is the distance between the y-intercept and the x-intercept of the line whose equation is y=3x+12

The distance between the y-intercept and the x-intercept of the line is 12.64911 units or units

Solution:

Given equation is y = 3x + 12

We have to find the distance between y-intercept and the x-intercept of the line whose equation is y = 3x + 12

Let us first find the x - intercept and y - intercept

The x-intercept is the point at which the line crosses the x-axis. At this point, the y-coordinate is zero.

The y-intercept is the point at which the line crosses the y-axis. At this point, the x-coordinate is zero

Finding x - intercept:

To find the x-intercept of a given linear equation, plug in 0 for 'y' and solve for 'x'.

Substitute y = 0 in given equation

y = 3x + 12

0 = 3x + 12

3x = -12

x = -4

Thus the x - intercept is (-4, 0)

Finding y - intercept:

To find the y-intercept, plug 0 in for 'x' and solve for 'y'

Substitute x = 0 in given equation

y = 3x + 12

y = 3(0) + 12

y = 12

Thus the y - intercept is (0, 12)

Now let us find the distance between x intercept and y intercept

Distance between two points is given by:

Here the distance between (-4, 0) and (0, 12) is given as:

Thus the distance between the y-intercept and the x-intercept of the line is 12.64911 units or units

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.