Let's assume that if a card has an even number on one side then it has a vowel on the other. we can see four cards: one has a 1 showing, another a 2 showing, another has an a showing, and the last has a b showing. which of the following is true?

a. we know the 2 has a vowel on the other side and the b has an odd number on the other side.
b. we know the a has an even number on the other side and the b has an odd number on the other side.
c. we know the 1 has consonant on the other side and the 2 has a vowel on the other side.
d. we know the 2 has a vowel on the other side and the a has an even number on the other

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.