The customer center in your company receives calls from customers who need with some of the customized software solutions your company provides. your company claims that the average waiting time is seven minutes at the busiest times, 8 a. m. to 10 a. m., monday through thursday. one of your main clients has recently complained that every time she calls during the busy hours, the waiting time exceeds seven minutes. you conduct a statistical study to determine the average waiting time with a sample of 35 calls for which you obtain an average waiting time of 8.15 minutes. if the value of your test statistic is less than the critical value, the correct decision is to the sample sizereduce the sample sizefail to reject the seven-minute average waiting time claimmaintain status quoreject the seven-minute claim

fail to reject the seven-minute average waiting time claim.

Step-by-step explanation:

As per given ,

Objective for test : the average waiting time is seven minutes or more.

Then ,

Since alternative hypothesis is right-tailed thus the test is an right-tailed test.

In a right tailed test , the rejection area lies on the right side of the critical value.

It means that if the observed z-value is greater than the critical value then it will fall into the rejection region other wise not.

i.e. If the value of your test statistic is less than the critical value, the correct decision is we fail to reject null hypothesis.

i.e. fail to reject the seven-minute average waiting time claim.

The complete statement would become:

If the value of your test statistic is less than the critical value, the correct decision is to fail to reject the seven-minute average waiting time claim.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

.25

step-by-step explanation: