which system of inequalities is represented by the graph?
a. y less than or equal to-2x+4 and y greater than or equal to x-6
b. y less than or equal to2x+4 and y greater than or equal to -x -6
c. y less than or equal to 2x-4 and y greater than or equal to -x-6
d. y less than or equal to 2x+4 and y greater than or equal to -x+6

The answer to your question is letter B

Step-by-step explanation:

Process

1.- Find two points of each line

Line A    (-2, 0)   (-1, 2)

Line B    (-1. - 5)   (-6, 0)

2.- Find the slope and equation of each line

Line A

                    m = 2

             y - 0 = 2(x + 2)

            y = 2x + 4

Line B

                    m = -1

             y - 0 = -1(x + 6)

             y = -x - 6

3.- Find the inequalities

Line A, we are interesteed in the lower area of the line, so the inequality is

                      y ≤ 2x + 4

Line B, we are also interested in the lower area of the line so the inequality is

                      y ≥ - x - 6

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!