In a large casino, the house wins on one of its games with a probability of 50.6%. all bets are 1: 1. if you win, you gain the amount you bet; if you lose, you lose the amount you bet. if you play 180 games in an evening, betting $1 each time, how much should you expect to win or lose?

E(x) = - $ 2.16

Step-by-step explanation:

If the house wins on one of  its games with a probability of 50.6 % (0.506), then you lose 180*0.506 games, it means you lose in 91.08 games, how your bet by game $1, then you lose $91.08.

You win in 180-91.08 = 88.92 games; how you gain the amount you bet, then you gain $88.92.

Thus the expect value of your gain is:

E(x) = 88.92 - 91.08

E(x) = - $ 2.16

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step-by-step explanation:

at least i think its

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