Ask your teacher an article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 183 of these passed the probe. assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe. (round your answers to three decimal places.)

The 95% (two-sided) confidence interval for the proportion of all dies that pass the probe is (0.462, 0.566).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

Z is the zscore that has a pvalue of .

For this problem, we have that:

356 dies were examined by an inspection probe and 183 of these passed the probe. This neabs that

95% confidence interval

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 95% (two-sided) confidence interval for the proportion of all dies that pass the probe is (0.462, 0.566).

f(x) is   are being squared

g(x) is   increasing by 2

h(x) is adding .25 each time

k(x) is taking the square root

f(x) and k(x) are exponential functions

the answer to this in exact form is 4/35 but in decimal form its 0.1142857

hope this if needed hmu