Mathematics, 17.12.2019 05:31 mlbaker265
Solve (x + 3)2 + (x + 3) β 2 = 0. let u = rewrite the equation in terms of u. (u2 + 3) + u β 2 = 0 u2 + u β 2 = 0 (u2 + 9) + u β 2 = 0 u2 + u + 1 = 0 factor the equation. what are the solutions of the original equation?
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Solve (x + 3)2 + (x + 3) β 2 = 0. let u = rewrite the equation in terms of u. (u2 + 3) + u β 2 = 0 u...
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