The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of asian postmenopausal women who were vegans and another sample of such women who were omnivores. diet sample size sample mean sample sd vegan 85 5.10 1.05 omnivore 96 5.55 1.20 calculate a 99% ci for the difference between population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (use μvegan − μomnivore. round your answers to three decimal places.)

99% CI:

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

The MSE can be calculated as

The weighted sample size nh can be calculated as

The standard deviation then becomes

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

Then the confidence interval can be constructed as

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15