Suppose that prices of a gallon of milk at various stores in one town have a mean of $3.73$⁢3.73 with a standard deviation of $0.10$⁢0.10. using chebyshev's theorem, what is the minimum percentage of stores that sell a gallon of milk for between $3.43$⁢3.43 and $4.03$⁢4.03? round your answer to one decimal place.

At-least 88.89%

Step-by-step explanation:

As per given , we have

Population mean :

Standard deviation :  

Now , $3.43= $⁢3.73- 3(0.10) =

$⁢4.03 = $⁢3.73+3(0.10) =

i.e. $3.43 is 3 standard deviations below mean and $⁢4.03 is 3 standard deviations above mean .

To find :  the minimum percentage of stores that sell a gallon of milk for between $3.43 and $4.03.

i.e. to find minimum percentage of stores that sell a gallon of milk  lies within 3 standard deviations from mean.

According to Chebyshev, At-least of the values  lies with in from mean.

For k= 3

At-least of the values lies within from mean.

In percent =

Hence, the minimum percentage of stores that sell a gallon of milk for between $3.43 and $4.03 =  At-least  88.89%

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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