For what value of a does 9 = (startfraction 1 over 27 endfraction) superscript a + 3?
negative eleven-thirds
negative seven-thirds
seven-thirds
eleven-thirds

Step-by-step explanation:

We want to find the value of for which .

We rewrite with a base of 3 to get:

.

Recall that:

.

We now equate the exponents to get:

The first choice is correct

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer: it's upside down and i can't read it

step-by-step explanation: