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if a shelter had 200 animals in foster homes at the beginning of spring the number of animals in foster homes at the end of the summer could be represented by y=3000x+200. where x is the number of months and y is the number of animals

1) what form is y=3000x+200 written in

2)how many animals would be placed in foster homes after 3 months?

3) how many months would it take to place 6,200 animals

4) what is one point on the graph of this line

1) Slope-intercept form

2) 9200

3) 2 months

4) (0,200)

Step-by-step explanation:

A shelter had 200 animals in foster homes at the beginning of spring and the number of animals in foster homes at the end of the summer could be represented by  

y=3000x+200 (1)

Where x is the number of months and y is the number of animals.

1) The equation (1) is written in the slope-intercept form of a straight line equation.

2) After 3 months means x = 3 and the number of animals in the foster home after 3 months will be (3000 ×3 + 200) = 9200 (Answer)

3) Let after x months the animal population will become 6200.

So, 6200 = 3000x + 200

⇒ 3000x = 6000

⇒ x = 2 months (Answer)  

4) If we put x = 0 in equation (1), then we get y = 200.

So, (0,200) is a point on the graph of the line. (Answer)