In a certain fraction, the numerator is 4 less than the denominator. if 4 is added to both the numerator and the denominator , the resulting fraction is equal vhat was the original 8/12 fraction (not necessarily written in lowest terms

The original fraction was

Step-by-step explanation:

The correct question is

In a certain fraction, the numerator is 4 less than the denominator. If 4 is added to both the numerator and the denominator , the resulting fraction is equal to 8/12. What was the original  fraction (not necessarily written in lowest terms)

Let

x ----> the numerator of the original fraction

y ----> the denominator of the original fraction

we know that

so

the original fraction is

If 4 is added to both the numerator and the denominator , the resulting fraction is equal to 8/12

so

Solve for y

Find the value of x

therefore

The original fraction was

the answer is simply just 6n add the two together as they have an n