Asafe following distance while driving is two car lengths for every 10 miles per hour that you are traveling if you are traveling at 65 miles per hour how many car lengths is a safe following distance

The lengths of 13 car is safe following distance at 65 miles per hour.

Step-by-step explanation:

Given:

A safe following distance while driving is two Car lengths for every 10 miles per hour.

Now, to find the number of car lengths at 65 miles per hour.

As given at every 10 miles per hour while driving is 2 car lengths.

So,  we use unitary method to get the number of car lengths at 65 miles per hour:

At 10 miles per hour distance of lengths of car = 2.

So, by dividing we get at 1 miles per hour distance of lengths of car = 2 ÷ 10.

Now, at 65 miles per hour distance of lengths of car =

Therefore, the lengths of 13 car is safe following distance at 65 miles per hour.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: